Question

if width of hollow cylinder is 2 cm its internal diameter is 14 cm and height is 26 and both the ends of the cylinder open then find the total surface area of hollow cylinder


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Answer 1

Answer:

the total surface area=inner surface area+outer surface area+2(circular surface area)

Step-by-step explanation:

inner surface area=2× 22/7 × 14 ×26

=44×52

=2288

outer surface area=2 ×22/7 ×16×26

=2614 ⁶/7

circular surface area=2(outer circle area - inner circle area)

=2(π((r2)²-(r1)²)).

$r2 > r1$

= 2π(16²-14²)

=2π(256-196)

=2×22/7×60

= 377 ⅐

total surface area=

2288+2614 ⁶/7 + 377⅐

=2288+2614+ ⁶/7 + 377+⅐

=2288+2614+ 377+1

=5280 cm²

hence the answer

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Answer 2

Answer:

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