If wise is a parallelogram and <W=90°, then prove that WISE is rectangle
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Hey mate!!!
Given angle W is 90°
so this means opposite angle A would also be 90° (opposite angles of a parallelogram are equal)
and we know that in a parallelogram, adjacent angles sum = 180°
Adjacent angle of W is I
so angle W + angle I = 180°
90 + angle I = 180°
angle I = 180° - 90°
angle I = 90°
So here we get that angle I = 90°
This means opposite angle E would also be of 90° (opposite angles are equal in a parallelogram)
So we have
angle W = angle I = angle S = angle E = 90°
We know that ‘A parallelogram with all angles as 90° is a rectangle’
Hence WISE is a rectangle.
Hope it helps dear friend ☺️
Given angle W is 90°
so this means opposite angle A would also be 90° (opposite angles of a parallelogram are equal)
and we know that in a parallelogram, adjacent angles sum = 180°
Adjacent angle of W is I
so angle W + angle I = 180°
90 + angle I = 180°
angle I = 180° - 90°
angle I = 90°
So here we get that angle I = 90°
This means opposite angle E would also be of 90° (opposite angles are equal in a parallelogram)
So we have
angle W = angle I = angle S = angle E = 90°
We know that ‘A parallelogram with all angles as 90° is a rectangle’
Hence WISE is a rectangle.
Hope it helps dear friend ☺️
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