if work done by a body is 16830erg if it mass and velocity is decresed by1/2 and then increased by 3/7 then the energy acting up on it in joules and if you don't know answer for this please follow me and I will ask many more questions for you to increase your knowledge
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Answered by
31
The wordings are not at all clear. However, I do that sum by assumptions.
W = 16, 380 erg.
After the work is done, the body attains KE equal to W.
So 1/2 m v² = W
If mass decreased by 1/2, it becomes m/2. If speed v is increased by 3/7 then it becomes v * 10/7 = 10* v/7.
New Energy = 1/2 * 5m/7 * [ 10 v/7]²
= (500 / 343) * 1/2 * m v²
It is an increase of 157/343 th of W.
Increase = 157 / 343 * 16, 830 ergs
= 7, 703.5 ergs
= 7.7035 * 10⁻⁴ Joules. 1 J = 10⁷ ergs.
W = 16, 380 erg.
After the work is done, the body attains KE equal to W.
So 1/2 m v² = W
If mass decreased by 1/2, it becomes m/2. If speed v is increased by 3/7 then it becomes v * 10/7 = 10* v/7.
New Energy = 1/2 * 5m/7 * [ 10 v/7]²
= (500 / 343) * 1/2 * m v²
It is an increase of 157/343 th of W.
Increase = 157 / 343 * 16, 830 ergs
= 7, 703.5 ergs
= 7.7035 * 10⁻⁴ Joules. 1 J = 10⁷ ergs.
kvnmurty:
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Answered by
9
W = 16, 380 erg.
After the work is done, the body attains KE equal to W.
So 1/2 m v² = W
then it becomes v * 10/7 = 10* v/7.
New Energy = 1/2 * 5m/7 * [ 10 v/7]²
= (500 / 343) * 1/2 * m v²
It is an increase of 157/343 th of W.
Increase = 157 / 343 * 16, 830 ergs
= 7, 703.5 ergs
= 7.7035 * 10⁻⁴ Joules. 1 J = 10⁷ ergs
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