If work done in moving a charge of 20 mC from infinity to a point O in an electric field is 15 J, then what is the electric potential at this point?
[Ans. 7.5 x 102V]
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Answer: 750 V
Explanation:
V=W\Q
W=15J
Q=20mC or 0.02C
therefore,15J/0.02C
=750V
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