Question

If x= 1/10 and y= -3/8, then evaluate x+y ,x-y ,x*y, and x÷ y​

Answer 1

Answer:

-0.3, 0.475, -3/80, -4/15

Step-by-step explanation:

Given that x= 1/10 and y= -3/8

So,

x + y = (1/10) + (-3/8) = (8 - 30)/80 = -24/80 = -3/10 = -0.3

x - y = (1/10) - (-3/8) = (1/10) + (3/8) = 38/80 = 19/40 = 0.475

x*y = (1/10) × (-3/8) = -3/80

x ÷ y​ = (1/10) ÷ (-3/8) = (1/10) × -(8/3) = -8/30 = -4/15

Answer 2

Given:$x=\frac{1}{10} and y=-\frac{3}{8}$

We have to find$x+y,x-y,x\times y,\frac{x}{y}$.

For this, we will put values of $x$and$y$ in the equation to find the value of$x+y,x-y,x\times y,\frac{x}{y}$.

We are solving in the following way:

We have$x=\frac{1}{10} and y=-\frac{3}{8}$

Now,

$=>x+y=\frac{1}{10} -\frac{3}{8} \\\\=>-0.275\\\\=>x-y=\frac{1}{10} +\frac{3}{8} \\\\=>0.475\\\\=>x\times y=\frac{1}{10} \times-\frac{3}{8} \\\\=>-0.0375$

$=>\frac{x}{y} =\frac{1}{10}\times -\frac{8}{3} \\\\=>-0.266$

Hence, the value of $x+y,x-y,x\times y,\frac{x}{y}$ will be

$-0.275,0.475,-0.0375,-0.266$.