Question

if x-1-√2 find the value of x-1/x

Answer 1

the answer is -1/x
if my answer is correct please mark me as brainliest

Answer 2

Here's your answer !!

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It's given that,

$= > x = 1 - \sqrt{2}$

We have to find value of ,

$= > x - \frac{1}{x} .........(1)$

Now,

$if \: x = 1 - \sqrt{2}$

So,

$= > \frac{1}{x} = \frac{1}{1 - \sqrt{2} }$

We will not rationalize it ,

$= > \frac{1}{1 - \sqrt{2} } \times \frac{1 + \sqrt{2} }{1 + \sqrt{2} }$

$= > \frac{1 + \sqrt{2} }{ {(1)}^{2} - {( \sqrt{2}) }^{2} }$

$= > \frac{1 + \sqrt{2} }{ - 1} \\ = > - (1 + \sqrt{2})$

$= > \frac{1}{x} = - (1 + \sqrt{2})$

By putting value of x and 1/x in equation (1),we get :-

$= > x + \frac{1}{x} = 1 - \sqrt{2} - ( - (1 + \sqrt{2} ) \\ = > x + \frac{1}{x} = 1 - \sqrt{2} + 1 + \sqrt{2}$

$- \sqrt{2} \: and \: \sqrt{2} \: get \: cancelled$

$= > x + \frac{1}{x} = 2$

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Hope it helps you !! :)