if x=-1/2 is a solution of the quadratic equation 3x^2+2kx-3=0 find the value of K
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Answered by
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3(-½)²+2(½)k-3=0
3x¼+k-3=0
0.75-3+k=0
k=2.25
plzz mark it as brainliest answer uf it helped u please
3x¼+k-3=0
0.75-3+k=0
k=2.25
plzz mark it as brainliest answer uf it helped u please
Answered by
12
SOLUTION :
Given : 3x² + 2kx - 3 = 0
Since, x = - 1/2 is a solution of given equation, so it will satisfy the equation.
On putting x = -½ in given equation,
3x² + 2kx - 3 = 0
3(-1/2)² + 2k(-1/2) − 3 = 0
3 × ¼ - k - 3 = 0
¾ - k - 3 = 0
k = ¾ - 3
k = (3 - 12)/4
k = - 9/4
Hence, the value of k is - 9/4.
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