Math, asked by m6941singh, 1 year ago

if x=-1/2 is a solution of the quadratic equation 3x^2+2kx-3=0 find the value of K

Answers

Answered by shaiksalman580
9
3(-½)²+2(½)k-3=0
3x¼+k-3=0
0.75-3+k=0
k=2.25

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Answered by mathsdude85
12

SOLUTION  :

Given : 3x² + 2kx - 3 = 0

Since, x = - 1/2  is a solution of given equation, so it will satisfy the equation.

On putting x = -½  in given equation,

3x² + 2kx - 3 = 0

3(-1/2)² + 2k(-1/2) − 3 = 0

3 × ¼ - k - 3 = 0

¾ - k - 3 = 0

k = ¾ - 3  

k = (3 - 12)/4

k = - 9/4  

Hence, the value of k is - 9/4.

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