Question

If x = 1/2 is a zero of the polynomial f(x) = 8x3 + ax2 – 4x + 2, find the value of a.​

Answer 1

Step-by-step explanation:

8(1/2) + a(1/2)^2 - 4(1/2) +2

4 + a/4 -2 +2

4+a/4

(16+a)/4 =0

16+a =0

a = -16

Answer 2

Answer:

Step-by-step explanation:

f(x) = 8x^3 + ax^2 - 4x +2

We know that X is a factor of f(x)

Which means remainder will be 0

then,

placing the value of x

(* f(x)= 0)

f(x) = 8 x 1/2^3 + a x 1/2^2 - 4 x 1/2 + 2 = 0

     = 1 + a/4 - 2 + 2 = 0

     = a/4 = -1

     = a = -1/4

(note = x^2 and the terms with sign ^ means x to the power 2 same with others) Mark as brainliest pls