Math, asked by geetangalimahapatra, 10 months ago

If x = 1/2 is azero of the polynomial p(x) = 8xcube– ax² – x +2
find the value of a​

Answers

Answered by thpanda11
2

Answer: 10

Step-by-step explanation:

As x=1/2 is a zero of p(x) = 8x³ - ax² - x + 2,

    8 × (1/2)³ - a × (1/2)² - 1/2 + 2 = 0

⇒  8 × (1/8) - (a/4) + 3/2 = 0

⇒  1 - (a/4) + 3/2 = 0

⇒  5/2 - (a/4) = 0

⇒  a/4 = 5/2

⇒  a = 4 × 5/2

⇒  a = 10

Answered by harsha921
1

Answer:

a=10

Step-by-step explanation:

x=1/2,pof 1/2=8*1/8-a*1/4-1/2+2=1-a/4+3/2=5/2-a/4=0=a/2=5/4,,a=10

Similar questions