If x = 1/2 is azero of the polynomial p(x) = 8xcube– ax² – x +2
find the value of a
Answers
Answered by
2
Answer: 10
Step-by-step explanation:
As x=1/2 is a zero of p(x) = 8x³ - ax² - x + 2,
8 × (1/2)³ - a × (1/2)² - 1/2 + 2 = 0
⇒ 8 × (1/8) - (a/4) + 3/2 = 0
⇒ 1 - (a/4) + 3/2 = 0
⇒ 5/2 - (a/4) = 0
⇒ a/4 = 5/2
⇒ a = 4 × 5/2
⇒ a = 10
Answered by
1
Answer:
a=10
Step-by-step explanation:
x=1/2,pof 1/2=8*1/8-a*1/4-1/2+2=1-a/4+3/2=5/2-a/4=0=a/2=5/4,,a=10
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