If x=-1/2 is zero of polynomial 8x^3-k
Find the value of k
Answers
Answered by
11
if -1/2 is the zeroes of p(x)
then, .
p(-1/2) = 0
8 ( -1/2)^3 - k = 0
8* -1/8 - k = 0
-1 - k =0
k = -1 Answer .
then, .
p(-1/2) = 0
8 ( -1/2)^3 - k = 0
8* -1/8 - k = 0
-1 - k =0
k = -1 Answer .
Answered by
0
Answer:
then
p(-1/2)^3-k=0
8*-1/8-k=0
-1-k=0
k=-1 ans
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