Question

If x=1-√2 then find the value of (x-1/x)whole cune​

Answer 1

Answer:

X=1-√2.

1/X=1/1-√2*1+√2/1+√2.

1/X=1+√2

(x-1/x)3= x3-l/x3-3(x-1/x)

(1-√2+1+√2)3 -3(1_√2+1+√2)

(2)3-6

8-6

2 Answers