Question

if √x+1/2√x=3;x²+1/16x²=?​

Answer 1

${\huge {\mathfrak {Answer :-}}}$

➡️ x + 1/4x = (3)^2 - 1 = 8

➡️ x^2 + 1/16x^2 = (8)^2 - 1/2 = 127/2.

Hence, 127/2 is the answer.

That's it..

Answer 2

Sec theta = x+1/4x Sec²theta = (x+1/4x)²1+tan²theta = x²+1/16x²+1/2 tan²theta = x²+1/16x²+1/2-1tan²theta = x²+1/16x²-1/2tan theta = +-(x-1/4x)when tan theta = +(x-1/4x)then, sec theta+tan theta = x+1/4x+x-1/4x => 2xwhen tha theta = -(x-1/4x)then, sec theta +tan theta = x+1/4x-(x-1/4x) =x+1/4x-x+1/4x=> 1/2x So, sec theta +tan theta = 2x or 1/2x

mark me as brainlyest answer