Question

IF (x-1/3)³= x³-x²+ax=1/27 the valve of a is:​

Answer 1

Answer:

a = 1/9

Step-by-step explanation:

(x-1/3)³= x³-x²+ax=1/27

(x-1/3)³ = x³ - (1/3)³ - 3(x)(1/3)² + 3(x)²(1/3)

{ (a-b)^3 = a^3-b^3-3ab^2+3a^2b }

(x-1/3)³ = x³ - 1/27 - 3x(1/9) + 3(x)²(1/3)

(x-1/3)³ = x³ - 1/27 - x/9 + x²

Given that,

x³ - 1/27 - x/9 + x² = x³ - x² + ax - 1/27

By comparing the coefficients of variables on both sides. We get,

x³ = x³

+ x² = + x²

- 1/27 = - 1/27

ax = x/9 => a = 1/9