If x= 1/(3-√8), find the value of x³-2x²-7x+5
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Step-by-step explanation:
\frac{1}{2- \sqrt{3} } = \frac{1}{2- \sqrt{3} } * \frac{2+ \sqrt{3}}{2+ \sqrt{3} } = \frac{ 2+ \sqrt{3}}{2^2-3}=\frac{ 2+ \sqrt{3}}{1} = 2+ \sqrt{3}
x³ - 2x² - 7x + 5
(2+ \sqrt{3})^3 - 2(2+ \sqrt{3})^2 - 7(2+ \sqrt{3}) + 5
8 + 3 \sqrt{3} + 6 \sqrt{3} (2+ \sqrt{3}) - 2(4+3+4 \sqrt{3}) - 7(2+ \sqrt{3}) + 5
8 + 3 \sqrt{3} + 12 \sqrt{3} + 18 - 14-8 \sqrt{3} - 14-7 \sqrt{3} + 5
31 + 15 \sqrt{3} - 28-15 \sqrt{3}
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root9001:
but i can't understand it!!!
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Here is your answer
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