Math, asked by root9001, 11 months ago

If x= 1/(3-√8), find the value of x³-2x²-7x+5 ​

Answers

Answered by GENIUS1223
3

Answer:

Step-by-step explanation:

\frac{1}{2- \sqrt{3} } =  \frac{1}{2- \sqrt{3} } * \frac{2+ \sqrt{3}}{2+ \sqrt{3} } =  \frac{ 2+ \sqrt{3}}{2^2-3}=\frac{ 2+ \sqrt{3}}{1} = 2+ \sqrt{3}

x³ - 2x² - 7x + 5

(2+ \sqrt{3})^3 - 2(2+ \sqrt{3})^2 - 7(2+ \sqrt{3}) + 5

8 + 3 \sqrt{3} + 6 \sqrt{3} (2+ \sqrt{3}) - 2(4+3+4 \sqrt{3}) - 7(2+ \sqrt{3}) + 5

8 + 3 \sqrt{3} + 12 \sqrt{3} + 18 - 14-8 \sqrt{3} - 14-7 \sqrt{3} + 5

31  + 15 \sqrt{3} - 28-15 \sqrt{3}

3


root9001: but i can't understand it!!!
Answered by Rashmi4444
11

Answer:

Here is your answer

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