Question

if [x-1]³ =8 what is the value of [x+1]²? 

Answer 1

given us (x-1)^3=8, x-1=2, so x=3 nw (x+1)^2=(3+1)^2=16

Answer 2

Answer:

The value of $[x+1]^{2}$ is 16

Given:

$[x-1]^{3}=8$

To find:

$[x+1]^{2}$

Solution:

To find the value of x,

$[x-1]^{3}=8$

$[x-1]=(8)^{\frac{1}{3}}$

$[x-1]=2$

$x=3$

Then, $[x+1]^{2}$ is,

$[x+1]=3+1$

$[x+1]=4$

$[x+1]^{2} \Rightarrow 4^{2}$

$[x+1]^{2}=16$

Any polynomial with a degree of two is called as a quadratic polynomial. Such types of equations involving quadratic polynomials were called as quadratic equations.

Similarly, a polynomial with a degree of three is called as a cubic polynomial. Such types of equations involving cubic polynomials were called as cubic equation.