Question

if x=1/3 and y=6/7 ,then xy-y/x=​

Answer 1

Answer:-

Given,

$x = \frac{1}{3} , \: y = \frac{6}{7}$

[ substitute the values]

$\frac{1}{3} \times \frac{6}{7} - \frac{ \frac{6}{7} }{ \frac{1}{3} }$

$\frac{6}{(3 \times 7)} - \frac{6}{7} \times \frac{3}{1}$

$[ \: \frac{6}{21} = \frac{2}{7} (simplify) \: ]$

$\frac{2}{7} - \frac{18}{7}$

$= \frac{ - 16}{7}$

$<strong><u>Therefore \: if \: x= \frac{1}{3} \: and \: y= \frac{6}{7} , \\ then \: xy - \frac{x}{y} = \: \frac{ - 16}{7}</u></strong>$

Answer 2

Answer:

$\frac{-16}{7}$