if x = -1/3 is a zero of a polynomial .p(x)= 27 x³ -ax²-x+3, then find the value of a.
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27 (1/3)^3- a(1/3)^2 + (1/3)+ 3= 0
-1-a/9+1/3+3=0
(a+3)/3=-2
a/3=-5
a=-15
-1-a/9+1/3+3=0
(a+3)/3=-2
a/3=-5
a=-15
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Answer:
the correct answer is -15
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