Question

if x=-1/3 is zero of polynomial p(x)=27x³-ax²-x+3,find the value of a

Answer 1

x=-1/3
therefore on substituting the value of x we get,

27(-1/3)³ -a(-1/3)² -(-1/3) +3=

-1 -a/9+1/3+3=0
thus, a=21