if x=-1/3 is zero of polynomial p(x)=27x³-ax²-x+3,find the value of a
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x=-1/3
therefore on substituting the value of x we get,
27(-1/3)³ -a(-1/3)² -(-1/3) +3=
-1 -a/9+1/3+3=0
thus, a=21
therefore on substituting the value of x we get,
27(-1/3)³ -a(-1/3)² -(-1/3) +3=
-1 -a/9+1/3+3=0
thus, a=21
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