if x+1/=5find the value of x2+1/x2
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Answered by
1
Hey mate!
Here is your answer > >
x+1/x=5
Squaring both sides
( x + 1 / x )^2=5^2
x^2+1/x^2+2=25
x^2+1/x^2=25-2
x^2+1/x^2=23
Hope it helps!
Thankyou ☆ ☆
Here is your answer > >
x+1/x=5
Squaring both sides
( x + 1 / x )^2=5^2
x^2+1/x^2+2=25
x^2+1/x^2=25-2
x^2+1/x^2=23
Hope it helps!
Thankyou ☆ ☆
Answered by
1
A2A
x2−(1x)2=(x+1x)(x−1x)
We know that (a+b)2=(a−b)2+4ab
Hence, (x+1x)2=(x−1x)2+4⋅x⋅1x=25+4=29
Hence the required solution is ±529−−√29
I hope this will help you
x2−(1x)2=(x+1x)(x−1x)
We know that (a+b)2=(a−b)2+4ab
Hence, (x+1x)2=(x−1x)2+4⋅x⋅1x=25+4=29
Hence the required solution is ±529−−√29
I hope this will help you
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