if (x-1) and (x-2) are the factors of P(x)= x3-3ax2+5x+b, find a and b
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Answer:
ehxiajri2wijsajakwowo
Answered by
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Answer:
please make me as a brainy
Step-by-step explanation:
first we take ( x-1 )
so, x = 1
put x=1 in give equation
1 - 3a+5+b=O
b-3a=-6 .........(1)
now, we take (x-2)
so, X=2
put it in give equation
8-6a+10+b=0
b-6a=-18 .........(2)
intersect equation 1 and 2
b-6a=-18
b-3a=-6
so it becomes
a= -4
than put a in any equation
b-3(-4)=-6
b+12=-6
b=-18
so the answer is
(a,b) = (-4,-18)
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