Math, asked by akii9, 1 year ago

If x=1 and y=-3 then find the value of k in 3x-4y+k=0


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Answers

Answered by mishrapm1010
5
If x=1
y=--3
then the value of 3x-4y+k=0
by putting the values we get,
3(1)-4(-3)+k=0
3+12+k=0
k=--15
hope it helps...

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Answered by ck233
0

put the value of x and y in the given equation

we find that

3×(1)-4(-3)+k=0

3+12+k=0

15+k=0

k=-15

hope it helps you

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