If x=1 and y=-3 then find the value of k in 3x-4y+k=0
Prerna233:
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Answered by
5
If x=1
y=--3
then the value of 3x-4y+k=0
by putting the values we get,
3(1)-4(-3)+k=0
3+12+k=0
k=--15
hope it helps...
y=--3
then the value of 3x-4y+k=0
by putting the values we get,
3(1)-4(-3)+k=0
3+12+k=0
k=--15
hope it helps...
Answered by
0
put the value of x and y in the given equation
we find that
3×(1)-4(-3)+k=0
3+12+k=0
15+k=0
k=-15
hope it helps you
royal jaat
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