if X = 1 is a common root of ax square + ax + 2 = 0 and X square + X + b = 0 then ab=?
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a is 3
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SOLUTION :
Option (b) is correct : 2
Given : ax² + ax + 2 = 0 ……….(1)
and x² + x + b = 0 ……………(2)
Since, x = 1 is a root of both the given equation, so it will satisfy both the equation.
For eq 1 :
On putting x = 1 in given equation,
ax² + ax + 2 = 0
a(1)² + a(1) + 2 = 0
a + a + 2 = 0
2a + 2 = 0
2a = - 2
a = - 2/2
a = - 1
For eq 2 :
x² + x + b = 0
1² + 1 + b = 0
1 + 1 + b = 0
2 + b = 0
b = - 2
The value of 'ab’ = - 1 × - 2
ab = 2
Hence, the value of ab is 2 .
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