If x=1 is a common root of equation ax2+ax+3=0 and x2+x+b=0
then ab=
a) 3 b)3.5 c)6 d)-3
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right answer is d(-3)
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Answer
Given x=1 is a common root of both the equation then
putting x=1 in ax²+ax+3
a(1)²+a(1)+3=0
a+a+3=0
2a+3=0
2a= - 3
a= -3/2
Now in x²+x+b
1+1+b=0
2+b=0
b= - 2
Now , ab = - 3/2 * - 2/1 =6/2 =3
ab=3 ans
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