Question

if X + 1 is a factor of a x cube + x square + 2 X + 4 - 9 find the value of a

Answer 1

asus phone will be not the factor of given p(x)

Answer 2

=>x+1=0
=>x=-1
Now,
p(x)=ax^3+x^2+2x+4-9=0

=>-a+1-2+4-9=0

=>-a+5-11=0

=>-a-6=0

=>a=-6

Hope this will help u
:-)