Question

If (x + 1) is a factor of ax^2 + bx + c; then
(A)a+b+c=0
(B)a+b=c
(C)a+c=b​

Answer 1

See the value of x =-1

ax^2+bx+c=0

a(-1)^2 +b(-1)+c=0

a-b+c=0

a+c=b is the answer

Pls mark me as brainliest

Thank you

Hope it helps you

Answer 2

Answer: The relation between a, b and c is given by : a + c = b

Step-by-step explanation:

Let ax² + bx + c be equal to p(x).

p(x) = ax² + bx + c

If x+1 is a factor of p(x), it means p(x) is exactly divisible by (x+1), then p(x) can be written in the form (x+1)g(x), where g(x) is a polynomial of degree 1.

p(x) = (x + 1).g(x)

Substituting x = -1,

p(-1) = (-1 + 1).g(-1)

p(-1) = 0.g(-1)

p(-1) = 0

p(x) = ax² + bx + c

Substituting x = -1,

p(-1) = a(-1)² + b(-1) + c

0 = a - b + c

a + c = b

#SPJ2