Math, asked by crispinrs, 1 year ago

if x+ 1 is a factor of ax power 3 + x power 2 - 2x + 4a - 9 find the value of ' a '

Answers

Answered by pianssiii
0
x+1=0
x=-1
axcube+xsq-2x+4a-9
=a*(-1)cube+x(-1)sq+4a-9=0
=a*-1+1+2+4a-9=0
=-1a+3+4a-9=0
=3a-6=0
=3a=6
=a=6/3
=2 answer
Answered by Anonymous
0
Hi there !

Given :-

[ x+ 1 ] is a factor of ax³ + x² - 2x + 4a + 9

Hence , 
-1 is a zero of the polynomial

p(-1) = ax³ + x² - 2x + 4a - 9

a
× [-1]³+ [ -1 ]²  - 2 × - 1 +  4a - 9 = 0

-a + 1 + 2+  4a - 9 = 0

3a - 6 = 0

3a = 6

a = 6/3

a = 2

Anonymous: answer is 2 dear
Anonymous: how ? :)
Anonymous: u missed to add -2x
Anonymous: sorry !
Anonymous: edit option :)
Anonymous: it's okk :)
Anonymous: can u send an edit option ?
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