if x+ 1 is a factor of ax power 3 + x power 2 - 2x + 4a - 9 find the value of ' a '
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Answered by
0
x+1=0
x=-1
axcube+xsq-2x+4a-9
=a*(-1)cube+x(-1)sq+4a-9=0
=a*-1+1+2+4a-9=0
=-1a+3+4a-9=0
=3a-6=0
=3a=6
=a=6/3
=2 answer
x=-1
axcube+xsq-2x+4a-9
=a*(-1)cube+x(-1)sq+4a-9=0
=a*-1+1+2+4a-9=0
=-1a+3+4a-9=0
=3a-6=0
=3a=6
=a=6/3
=2 answer
Answered by
0
Hi there !
Given :-
[ x+ 1 ] is a factor of ax³ + x² - 2x + 4a + 9
Hence ,
-1 is a zero of the polynomial
p(-1) = ax³ + x² - 2x + 4a - 9
a× [-1]³+ [ -1 ]² - 2 × - 1 + 4a - 9 = 0
-a + 1 + 2+ 4a - 9 = 0
3a - 6 = 0
3a = 6
a = 6/3
a = 2
Given :-
[ x+ 1 ] is a factor of ax³ + x² - 2x + 4a + 9
Hence ,
-1 is a zero of the polynomial
p(-1) = ax³ + x² - 2x + 4a - 9
a× [-1]³+ [ -1 ]² - 2 × - 1 + 4a - 9 = 0
-a + 1 + 2+ 4a - 9 = 0
3a - 6 = 0
3a = 6
a = 6/3
a = 2
Anonymous:
answer is 2 dear
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