If (x – 1) is a factor of p(x) =x ^2 + x + k , then find the value of k .
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0
Answer:
If x−1 is the factor of the equation then put x=1 in these equation
(i) x
2
+x+k=0⇒(1)
2
+1+k=0⇒1+1+k=0⇒k=−2
(ii) 2x
2
+kx+
2
=0⇒2(1)
2
+k(1)+
2
=0⇒2+k+
2
=0⇒k=−2−
2
(iii) kx
2
−
2
x+1=0⇒k(1)
2
−
2
(1)+1=0⇒k−
2
+1=0⇒k=
2
−1
(iv) kx
2
−3x+k=0⇒k(1)
2
−3(1)+k=0⇒k−3+k=0⇒2k=−3⇒k=−
2
3
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