if x+1 is a factor of square of x-3ax +3a-7
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Answered by
5
Your question needs a correction,
Correct question : find the value of a
By factor theorem, x = -1
x² - 3ax + 3a - 7 = 0
(-1)² - 3a(-1) + 3a - 7 = 0
1 + 3a + 3a - 7 = 0
6a - 6 = 0
6a = 6
a = 1
I hope this will help you
(-;
Correct question : find the value of a
By factor theorem, x = -1
x² - 3ax + 3a - 7 = 0
(-1)² - 3a(-1) + 3a - 7 = 0
1 + 3a + 3a - 7 = 0
6a - 6 = 0
6a = 6
a = 1
I hope this will help you
(-;
Answered by
5
Heya!
Here is yr answer.....
Given,
=> x² -3ax + 3a -7
x+1 is the factor of the above eq.
x+1 = 0
x = -1
Now,
(-1)² -3a(-1) + 3a -7 = 0
1 + 3a + 3a - 7 = 0
6a - 6 = 0
6a = 6
a = 6/6
a = 1
Hope it hlpz..
Here is yr answer.....
Given,
=> x² -3ax + 3a -7
x+1 is the factor of the above eq.
x+1 = 0
x = -1
Now,
(-1)² -3a(-1) + 3a -7 = 0
1 + 3a + 3a - 7 = 0
6a - 6 = 0
6a = 6
a = 6/6
a = 1
Hope it hlpz..
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