Math, asked by vnitesh145, 1 year ago

if x+1 is a factor of square of x-3ax +3a-7

Answers

Answered by abhi569
5
Your question needs a correction,

Correct question : find the value of a



By factor theorem, x = -1


x² - 3ax + 3a - 7 = 0

(-1)² - 3a(-1) + 3a - 7 = 0

1 + 3a + 3a - 7 = 0

6a - 6 = 0

6a = 6

a =  \frac{6}{6}
a = 1




I hope this will help you

(-;
Answered by Anonymous
5
Heya!

Here is yr answer.....


Given,

=> x² -3ax + 3a -7

x+1 is the factor of the above eq.

x+1 = 0

x = -1



Now,

(-1)² -3a(-1) + 3a -7 = 0

1 + 3a + 3a - 7 = 0

6a - 6 = 0

6a = 6

a = 6/6

a = 1



Hope it hlpz..




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