If x-1 is a factor of the polynomial 5x³ - 4x²+x-k, what number is k ?
Answers
Answered by
6
Answer:
k = -3/2
Step-by-step explanation:
p(x) = 5 x 3 + 4x² - 6x + 2k
x - 1 is a factor of p(x)
then, X-1 = 0
x=1
put x in p(x)
p(x) = 5x3 + 4x² - 6x + 2k
p(1) = 5(1)3 + 4(1)2 - 6(1) + 2k
= 5+ 4 - 6 + 2k
9 - 6 + 2k
3 + 2k
X-1 is a factor of p(x)
then p(x) = 0
so, 3+ 2k = 0
2k = -3
k = -3/2
Answered by
1
Answer:
Answer:
k = -3/2
Step-by-step explanation:
p(x) = 5 x 3 + 4x² - 6x + 2k
x - 1 is a factor of p(x)
then, X-1 = 0
x=1
put x in p(x)
p(x) = 5x3 + 4x² - 6x + 2k
p(1) = 5(1)3 + 4(1)2 - 6(1) + 2k
= 5+ 4 - 6 + 2k
9 - 6 + 2k
3 + 2k
X-1 is a factor of p(x)
then p(x) = 0
so, 3+ 2k = 0
2k = -3
k = -3/2
Similar questions