Question

If x-1 is a factor of x5-3x4-ax3+3ax2+2ax+4 then the value of a is

Answer 1

Answer:

answer =0

Step-by-step explanation:

Because x-1 is factor of. x5-3x4-ax3+3ax2+2ax+4

Therefore

Value of this equation is 0. (if. divisor is factor of divided then value is 0)

Answer 2

Answer:

The value of a is -1/2

Step-by-step explanation:

Let,

$f(x)=x^5-3x^4-ax^3+3ax^2+2ax+4$

Given,

x-1 is a factor of f(x)

i.e. x = 1 is a zero of f(x),

⇒ f(1) = 0

$\implies (1)^5-3(1)^4-a(1)^3+3a(1)^2+2a(1)+4=0$

$1-3-a+3a+2a+4=0$

Combining like terms,

$4a + 2 = 0$

$4a = -2$

$\implies a =-\frac{2}{4}=-\frac{1}{2}$

#Learn more :

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