if x +1 is factor of ax2+x2-2x+4a-9 find value of a
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x+1 is a factor
f(x)=ax²+x²-2x+4a-9
0=a(-1)²+(-1)²-2(-1)+4(a)-9
0=a+1+2+4a-9
0=5a-6
6/5=a
f(x)=ax²+x²-2x+4a-9
0=a(-1)²+(-1)²-2(-1)+4(a)-9
0=a+1+2+4a-9
0=5a-6
6/5=a
MOSFET01:
ye 2ax he ya 2ax²
Answered by
0
If x+1 is factor of ax^2+x^2-2x+4a-9
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