If (x+1) is said to be a factor of x2 + 2x + 1, then the remainder is option (A)1 (B) – 1 (C) 0 (D) cannot determine
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Answered by
1
Step-by-step explanation:
(-1)^2+2×-1+1
1-2+1
0
therefore the reminder is (c) 0
Answered by
0
Step-by-step explanation:
Using the identity : (a+b)²=a²+b²+2ab
We get : x²+2x+1
= (x)²+2(x)(1)+(1)²
= (x+1)(x+1)
Therefore, second factor of x²+2x+1
is (x+1)
Let's check it by dividing :
Verify the attachment to see division .
Remainder will be 0.
Attachments:
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