Question

the sum of two numbers is 72 if one of the number is 6 more than the other find the numbers​

Answer 1

Answer:

let other no. be 'x'

Step-by-step explanation:

one number = (x + 6)

sum = 72 (given)

x + (x + 6) = 72

2x = 66 => x = 33

first no.= 33

and second number is

= x + 6 = 33 + 6 = 39

required numbers are 33,39 Ans

Answer 2

Step-by-step explanation:

let the first number be x.

and another number be x+6.

x+x+6=72

2x+6=72

x=72-6/2

x=66/2

x=33

first number=33

second number=33+6=39

hope it helps