Question

If x+1 is the factor of this polynomial (x-1)(2x2+4x+p) then the value of p is

Answer 1

Answer:

Using factor theorem, if x + 1 is a factor of (x - 1 )( 2x^2 + 4x + p ), value of this polynomial should be 0 for the solution of x + 1.

So, here, x = - 1

= > ( - 1 - 1 )( 2(-1)^2 + 4(-1) + p ) = 0

= > -2( 2 - 4 + p ) = 0

= > - 2( - 2 + p ) = 0

= > - 2 + p = 0

= > p = 2

Hence the required value of p is 2.

Answer 2

so p=2

(its 2 not -2)

JAI SHREE KRISHAN