If x = 1 - root2, find the value of (x-1/x)^3
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4
Answer:
(x - 1/x)³ = 8
Solution:
- Given : x = 1 - √2
- To find : (x - 1/x)³ = ?
We have ;
x = 1 - √2
Thus,
1/x = 1/(1 - √2)
Now,
Rationalising the denominator of the term in RHS , we get ;
=> 1/x = (1 + √2) / (1 - √2)(1 + √2)
=> 1/x = (1 + √2) / (1² - √2²)
=> 1/x = (1 + √2) / (1 - 2)
=> 1/x = (1 + √2) / (-1)
=> 1/x = - (1 + √2)
Now,
=> x - 1/x = (1 - √2) - [ - (1 + √2) ]
=> x - 1/x = 1 - √2 + 1 + √2
=> x - 1/x = 2
Now,
Cubing both the sides , we get ;
=> (x - 1/x)³ = 2³
=> (x - 1/x)³ = 8
Hence , (x - 1/x)³ = 8
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