if x =1+, then find {x+²
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Answer:
We may construct two cases, depending on whether x>0, or x<0 ( Obviously x≠0 )
Case 1:
x>0
By applying the AM−GM inequality, we get:
x+1/x>=2
With equality holding for the case, x=1/x=1
So, x−1/x=0 , for x>0
Case 2:
x<0
If x<0 , then so is 1/x .
But, if both are less than 0 , then their sum must also be less than 0 , and hence cannot be 2 .
So, this case is void.
Hence, we get:
x−1/x=0 , for all real x satisfying x+1/x=2
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