Math, asked by mnnadeem368, 5 months ago

If x = 1 to 3, and y= 1 to 4, z = (x^2 + y2)/(x+y)
01) X = -13, y = 1:4, z= (X+Y)/(x+y)2; x.y] = maingrig(x,y)
02
None
03)
x = -1:3. y = 1:4. Z= (x+y)3./(x+y). [xy] =maingrig(x,y)
04)
x = -13, y = 1:4. Z= (x+y)3/(x+y)2 xy] =maingrigy​

Answers

Answered by abhinav2408
3

Answer:

don't know sorry brother

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