Question

if (x-1),(x+1)and(2x+3)are in AP then the value of x is
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Answer 1

Answer:

as (x-1),(x+1)and (2x+3) are in AP

so

(x+1)-(x-1)=(2x+3)-(x+1)

=> x+1-x+1=2x+3-x-1

=> 2=x+2

=> x=2-2=0

so the value of x is 0

Answer 2

Answer:

(X + 1 ) - (X - 1) =( 2 X + 3 )-(x+1)

X + 1 - X + 1 = 2X + 3 - x-1

2=x+2

x=0