Question

if x+1/x=12 find the value of x²+1/x²​

Answer 1

Answer:

x−x1

We have,

(x−x1)2=x2−2×x×x1+x21

⇒(x−x1)2=x2−2+x21

⇒(x−x1)2=x2+x21−2

⇒(x−x1)2=27−2[∵x2+x21=27 given]

⇒(x−x1)2=25⇒(x−x1)2

⇒x−x1=±5

              [Taking square root of both sides]

Answer 2

Answer:

142

Step-by-step explanation:

we have x+(1÷x)=12

{x+(1÷x)}square=x square+(1÷x) square+x×(1÷x)×2

now substituting x+(1÷x) square as12 square,

we get 144= x square+ (1÷x) square+2

hence,x square + (1÷x) square=144-2=142