Math, asked by mjameen9892, 9 months ago

If x+1/x=2 and x is real find the value of x^17+1/x^19?

Answers

Answered by Anonymous
1

Answer:

X+ 1/x = 2

Well its visible that x = 1 is satisfying above equation

1+1/1 = 1+1 = 2 as given

Or

x^2 +1 =>2x

x^2 - 2x +1= 0

(x-1)^2 = 0

x= 1

So, Put x= 1 in x^17 + 1/x^19

= 1+ 1/1

= 1+1

= 2

#answerwithquality #BAL

Answered by 3CHANDNI339
3

 \underline \mathbb{SOLUTION}

x  +  \frac{1}{x}  = 2

x = 1 satisfies above equation.

 =  > 1 +  \frac{1}{1 }

 =  > 1 + 1 = 2

 \underline \mathbb{OR}

 {x}^{2}  + 1 = 2x

 {x}^{2}  - 2x + 1 = 0

 {(x - 1)}^{2}  =  0

 =  > x = 1

 \underline \mathbb{SO}

putting \: x = 1 \: in \:   {x}^{17}  +  \frac{1}{ {x}^{19} }

 =  > 1  +  \frac{1}{1}

 =  > 1 + 1

 =  > 2

 \underline \mathbb{ANSWER= 2}

_______________________________________

#BAL

#Answerwithquality

Similar questions