If x + 1/x=2, find the value x^4-x^3
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Answer:
x+1x=4∣⋅x
x2+1=4x∣−4x
x2−4x+1=0∣(a±b)2=a2±2ab+b2
(x−2)2−3=0∣+3
(x−2)2=3∣√
x−2=±3–√∣+2
x=2±3–√
but for these values:
x2+1x3=11⋅(3∓3–√)≠12
so there is no solution.
As for x2+1x3=12 see
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