Question

if x+1/x=2 then find the value of (x)^64+(1/x)^64​

Answer 1

Answer: 2

Step-by-step explanation:

x+1/x=2

x^2+1/x^2=(x+1/x)^2-2=(2)^2-2

= 4-2=2

x^4+1/x^4=(x^2+1/x^2)^2-2= (2)^2-2

= 4-2=2

So, continue in this way, we always get formula as follows: (n is even)

x^n+1/x^n= [x^(n/2)+ 1/x^(n/2)]^2 - 2

x^64+1/x^64= (x^32+ 1/x^32)^2 - 2

= (2)^2- 2= 4-2=2

Answer 2

Answer:

this is the answer

Step-by-step explanation:

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