If x – (1/x) = 3, Evaluate x³ – (1/x³)
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x³ – (1/x³) = 36
Explanation:
Given x - 1/x = 3
Find x³ – (1/x³)
x - 1/x = 3
Squaring on both sides, we get
(x - 1/x)^2 = 3^2
x2 + 1/x2 -2 = 9
x2 + 1/x2 +1 = 12
Applying formula (a – b) (a2 + ab + b2 ), Let's expand
x³ – (1/x³) = (x – 1/x) (x2 + 1/x2 +1)
= 3 * 12
= 36
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