if x-1/x = 3 find x^2-1/x^2 and x^4+1/x^4
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math]\displaystyle x+\frac{1}{x}=3[/math]
[math]\displaystyle \left(x+\frac{1}{x}\right)^2=3^2[/math]
[math]\displaystyle x^2+\frac{1}{x^2}+2=9[/math]
[math]\displaystyle x^2+\frac{1}{x^2}=7 \tag 1[/math]
[math]\displaystyle\left(x^2+\frac{1}{x^2}\right)\left(x^2+\frac{1}{x^2}\right)=7 ×7[/math]
[math]\displaystyle x^4+\frac{1}{x^4}+2=49[/math]
[math] \displaystyle \mathbf{x^4+\frac{1}{x^4}=47}[/math]
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