if x+1/x=4 then how to x4+1/x4=198
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Answered by
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x+1/x=4
Squaring Both side
(x+1/x)²=4²
As we know (a+b)²=a²+b²+2ab
Now Using this identity
➡️(x+1/x)²=16
➡️x²+1/x²+2×x×1/x=16
➡️x²+1/x²+2=16
➡️x²+1/x²=16-2
➡️x²+1/x²=14
And (a-b)²=a²+b²-2ab
Using this identity
Now ,squaring Both side
(x²-1/x²)²=14²
➡️x⁴+1/x⁴-2×x²+1/x²=196
➡️x⁴+1/x⁴=196+2
x⁴+1/x⁴=198
Squaring Both side
(x+1/x)²=4²
As we know (a+b)²=a²+b²+2ab
Now Using this identity
➡️(x+1/x)²=16
➡️x²+1/x²+2×x×1/x=16
➡️x²+1/x²+2=16
➡️x²+1/x²=16-2
➡️x²+1/x²=14
And (a-b)²=a²+b²-2ab
Using this identity
Now ,squaring Both side
(x²-1/x²)²=14²
➡️x⁴+1/x⁴-2×x²+1/x²=196
➡️x⁴+1/x⁴=196+2
x⁴+1/x⁴=198
Answered by
0
x+1/x= 4
x+1 = 4x
1=4x-x = 3x
so X = 1/3
(1/3)4 +1 /(1/3)4 = l.h.s.
= (4/3) +1 / (4/3)
=[(4+3)/3]/(4/3)
=[(7/3)/(4/3)]
= 7/4
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