Question

If x-1/x=5 find, (a) x square+1/x square
(b) x^4+1/x^4

Answer 1

solution: – x-1/x=5 .........(1)
squaring both the side of (1)
(x-1 /x)²=(5)²
x²+1/x²-2x=25
x²+1/x² -2x•1/x=25
x²+1/x² -2=25
x²+1/x²=25+2
x²+1/x²=27

so the answer is –· x²+1/x² =27

Answer 2

a) let x-1/x =5 be equation 1
now squaring both side in equation 1
(x-1/x)^2=(5)^2
x^2+1/x^2-2×x×1/x=25
x^2+1/x^2-2=25
x^2+1/x^2=25-2
x^2+1/x^2=23
b) now take x^2+1/x^2=23 be equation 1
now squaring both side in equation 1
(x^2+1/x^4)^2 = (23)^2
x^4+1/x^4+2×x^4×1/x^4= 529
x^4+1/x^4+2 = 529
x^4+1/x^4=529-2
x^4+1/x^4=527

HOPE THIS HELPS U:)☺️