if x+1÷x=5,find the value of x^4+1÷x^4.
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Given,
x+1/x=5
Squaring on both side,we get.
(x+1/x)^2 = (5)^2
=>x^2+2.x.1/x+(1/x)^2=25
=>x^2+2+1/x^2=25
=>x^2+1/x^2=25-2
=>x^2+1/x^2=23
Squaring on both sides,we get.
(x^2+1/x^2)^2=(23)^2
=>(x^2)^2+2.x^2.1/x^2+(1/x^2)^2=529
=>x^4+2+1/x^4=529
=>x^4+1/x^4=529-2
=>x^4+1/x^4=527
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..НσρЄ ΙТ НЄℓρЅ Уσυ..
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Given,
x+1/x=5
Squaring on both side,we get.
(x+1/x)^2 = (5)^2
=>x^2+2.x.1/x+(1/x)^2=25
=>x^2+2+1/x^2=25
=>x^2+1/x^2=25-2
=>x^2+1/x^2=23
Squaring on both sides,we get.
(x^2+1/x^2)^2=(23)^2
=>(x^2)^2+2.x^2.1/x^2+(1/x^2)^2=529
=>x^4+2+1/x^4=529
=>x^4+1/x^4=529-2
=>x^4+1/x^4=527
❌❌❌❌❌❌❌❌❌❌❌❌❌
..НσρЄ ΙТ НЄℓρЅ Уσυ..
❌❌❌❌❌❌❌❌❌❌❌❌❌
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Answer:
If x + = 5 , find the values of x 1 : x 4 +1 x
Step-by-step explanation:
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