If (x -1/x)=5,the value of x sq +1/x sq is ?
Adithya1234:
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Answered by
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given (x-1/x)=5
(x-1/x)²=5²
(x-1/x)²=25
x²+1/x²-2×x×1/x=25
x²+1/x²-2=25
x²+1/x²=25+2
x²+1/x²=27
(x-1/x)²=5²
(x-1/x)²=25
x²+1/x²-2×x×1/x=25
x²+1/x²-2=25
x²+1/x²=25+2
x²+1/x²=27
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Answered by
1
use the formula a² + b² = [(a - b)² + 2ab].
x² + (1/x²) = [(x - 1/x)² + 2(x)(1/x)] = [(x- 1/x)² + 2] = (5² +2) = 25+2 = 27
x² + (1/x²) = [(x - 1/x)² + 2(x)(1/x)] = [(x- 1/x)² + 2] = (5² +2) = 25+2 = 27
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