If x+1\x=5 then find the value of x square +1\x square
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2
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x + 1 / x = 5
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on squaring both side, we get
( x + 1 / x )^2 = ( 5 )^2
x^2 + 1 /x^2 + 2 ( x ) (1 /x ) = 25
x^2 + 1 / x^2 + 2 = 25
x^2 + 1 /x^2 = 25 - 2
x^2 + 1 / x^2 = 23
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Your Answer : 23
_______________________________
x + 1 / x = 5
_______________________________
on squaring both side, we get
( x + 1 / x )^2 = ( 5 )^2
x^2 + 1 /x^2 + 2 ( x ) (1 /x ) = 25
x^2 + 1 / x^2 + 2 = 25
x^2 + 1 /x^2 = 25 - 2
x^2 + 1 / x^2 = 23
_______________________________
Your Answer : 23
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Answered by
3
the correct answer is: 23
squaring [x + (1/x)= 5]
x^2 + (1/x^2) + 2(x)(1/x) = 25
x^2 + (1/x^2) + 2 = 25
x^2 + (1/x^2) = 23
squaring [x + (1/x)= 5]
x^2 + (1/x^2) + 2(x)(1/x) = 25
x^2 + (1/x^2) + 2 = 25
x^2 + (1/x^2) = 23
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