Math, asked by rrinkeerrinkee198, 30 days ago

if x-1/x=8 fid the values of x^2+1/x^2) and (x^4+1/x^4)​

Answers

Answered by amansharma264
19

EXPLANATION.

⇒ (x - 1/x) = 8.

As we know that,

Squaring on both sides of the equation, we get.

⇒ (x - 1/x)² = (8)².

⇒ (x)² + (1/x)² - 2(x)(1/x) = 64.

⇒ x² + 1/x² - 2 = 64.

⇒ x² + 1/x² = 64 + 2.

⇒ x² + 1/x² = 66.

Again squaring on both sides of the equation, we get.

⇒ (x² + 1/x²)² = (66)².

⇒ (x²)²  (1/x²)² + 2(x²)(1/x²) = 4356.

⇒ x⁴ + 1/x⁴ + 2 = 4356.

⇒ x⁴ + 1/x⁴ = 4356 - 2.

⇒ x⁴ + 1/x⁴ = 4354.

Answered by Salmonpanna2022
20

Step-by-step explanation:

Given:-

x - 1/x = 8

To find out:-

Value of x^2 + 1/x^2 and x^4 + 1/x^4

Solution:-

We have,

x - 1/x = 8

On, squaring on both sides, we get

→ (x - 1/x)^2 = (8)^2

Now, applying algebraic Identity because our expression in the form of ;

(a - b)^2 = a^2 - 2ab + b^2

Where, we have to put in our expression a = x and b = 1/x ,we get

→ x^2 - 2(x)(1/x) + (1/x)^2 = (8)^2

→ x^2 - 2 + (1/x)^2 = 64

→ x^2 - 2 + 1/x^2 = 64

→ x^2 + 1/x^2 = 64 + 2

→ x^2 + 1/x^2 = 66

Now, again squaring on both sides, we get

(x^2 + 1/x^2)^2 = (66)^2

Now, applying algebraic Identity because our expression in the form of;

(a + b)^2 = a^2 + 2ab + b^2

Where, we have to put in our expression a = x and b = 1/x , we get

→ (x^2)^2 + 2(x^2)(1/x^2) + (1/x^2)^2 = (66)^2

→ x^4 + 2(x^2)(1/x^2) + 1/x^4 = 4356

→ x^4 + 2 + 1/x^4 = 4356

→ x^4 + 1/x^4 = 4356 - 2

→ x^4 + 1/x^4 = 4354

Answer:-

Hence, the value of x^2 + 1/x^2 is 66 and x^4 + 1/x^4 is 4354.

Used formulae:-

(a - b)^2 = a^2 - 2ab + b^2

(a + b)^2 = a^2 + 2ab + b^2

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